(1+i)*x^2-4x+4=0

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Solution for (1+i)*x^2-4x+4=0 equation:


Simplifying
(1 + i) * x2 + -4x + 4 = 0

Reorder the terms for easier multiplication:
x2(1 + i) + -4x + 4 = 0
(1 * x2 + i * x2) + -4x + 4 = 0

Reorder the terms:
(ix2 + 1x2) + -4x + 4 = 0
(ix2 + 1x2) + -4x + 4 = 0

Reorder the terms:
4 + ix2 + -4x + 1x2 = 0

Solving
4 + ix2 + -4x + 1x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + ix2 + -4x + -4 + 1x2 = 0 + -4

Reorder the terms:
4 + -4 + ix2 + -4x + 1x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + ix2 + -4x + 1x2 = 0 + -4
ix2 + -4x + 1x2 = 0 + -4

Combine like terms: 0 + -4 = -4
ix2 + -4x + 1x2 = -4

Add '4x' to each side of the equation.
ix2 + -4x + 4x + 1x2 = -4 + 4x

Combine like terms: -4x + 4x = 0
ix2 + 0 + 1x2 = -4 + 4x
ix2 + 1x2 = -4 + 4x

Add '-1x2' to each side of the equation.
ix2 + 1x2 + -1x2 = -4 + 4x + -1x2

Combine like terms: 1x2 + -1x2 = 0
ix2 + 0 = -4 + 4x + -1x2
ix2 = -4 + 4x + -1x2

Divide each side by 'x2'.
i = -4x-2 + 4x-1 + -1

Simplifying
i = -4x-2 + 4x-1 + -1

Reorder the terms:
i = -1 + -4x-2 + 4x-1

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